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Figure 3-1 shows the concepts of cloud Blob storage. Blob storage access is based on an account. An Azure account can create multiple Blob containers. A Blob container can be understood as a placeholder for a group of Blob storages. Blob storage can have metadata, which can be understood as a collection of header attributes. Blob storage can be partially updated and committed using block objects. Each Blob can own a set of metadata in NameValueCollection string format. The Microsoft specification for blob storage can be found in Appendix A.

Primary Unary Multiplicative Additive Shift Relational and type Equality Logical AND Logical XOR Logical OR Conditional AND Conditional OR

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The traditional way to access a relational database is to use Java Database Connectivity (JDBC). Some common problems with using JDBC directly are as follows: You must manually handle database connections. There is always the risk that connections aren t closed, which can lead to other problems. You have to write a lot of bulky code, because all the fields required for inserts, updates, and queries must be explicitly mentioned. You have to manually handle associations. For complex data, this can be a major issue. The code isn t portable to other databases.

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Figure 3-1. Cloud blob storage structure concepts The data object model of Azure Blob storage is shown in Figure 3-2. (This data map is generated using SQL Server Management Studio against the DevelopmentStorageDb on a local machine. The DevelopmentStorageDb database will be created the first time development storage is accessed and the local development storage is initialized by the Azure framework.) This database map actually reflects the concept diagram of Figure 3-1 and the relationship among the participants of all Blob storage tables. For example, a Blob container has an ID as its primary key, which is a foreign key of the Blob table. As I have mentioned, the local development environment and runtime environment fabric simulate the remote cloud environment. In the Azure cloud environment a physical table may have multiple instances running from distinct remote virtual machines.

If all the operators in an expression have different levels of precedence, then evaluate each sub-expression, starting at the one with the highest level, and work down the precedence scale. But what if two sequential operators have the same level of precedence For example, given the expression 2 / 6 * 4, there are two possible evaluation sequences: (2 / 6) * 4 = 4/3 or 2 / (6 * 4) = 1/12 When sequential operators have the same level of precedence, the order of evaluation is determined by operator associativity. That is, given two operators of the same level of precedence, one or the other will have precedence, depending on the operators associativity. Some important characteristics of operator associativity are the following, and are summarized in Table 8-5: Left-associative operators are evaluated from left to right. Right-associative operators are evaluated from right to left. Binary operators, except the assignment operators, are left-associative. The assignment operators and the conditional operator are right-associative. Therefore, given these rules, the preceding example expression should be grouped left to right, giving (2 / 6 ) * 4, which yields 4/3. Table 8-5. Summary of Operator Associativity

You can explicitly set the order of evaluation of the sub-expressions of an expression by using parentheses. Parenthesized sub-expressions Override the precedence and associativity rules Are evaluated in order from the innermost nested set to the outermost

<nested-composite-element name="phone" class="Phone"> <property name="areaCode" type="string" column="PHONE_AREA_CODE" /> <property name="telNo" type="string" column="PHONE_TEL_NO" /> </nested-composite-element> <many-to-one name="address" class="Address" column="ADDRESS_ID" /> </composite-element> </map> </class> </hibernate-mapping> For the map-key component to work properly, you need to override the equals() and hashCode() methods of the component class: public class Period { ... public boolean equals(Object obj) { if (!(obj instanceof Period)) return false; Period other = (Period) obj; return new EqualsBuilder().append(startDate, other.startDate) .append(endDate, other.endDate) .isEquals(); } public int hashCode() { return new HashCodeBuilder().append(startDate) .append(endDate) .toHashCode(); } }

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