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Suppose that you place an ac voltage across a low-loss coil, with a frequency high enough so that the inductive reactance, XL, is much larger than the resistance, R. In this situation, the current is one-quarter of a cycle behind the voltage. That is, the current lags the voltage by 90 degrees (Fig. 13-8). At very low frequencies, large inductances are normally needed in order for this current lag to be a full 1 4 cycle. This is because any coil has some resistance; no wire is a perfect conductor. If some wire were found that had a mathematically zero resistance, and if a coil of any size were wound from this wire, then the current would lag the voltage by 90 degrees in this inductor, no matter what the ac frequency. When the value of XL is very large compared with the value of R in a circuit that is, when there is an essentially pure inductance the vector in the RL plane points straight up along the XL axis. Its angle is 90 degrees from the R axis, which is considered the zero line in the RL plane.

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= tan 1 (XL/R) or = arctan (XL/R)

When the resistance in a resistance-inductance circuit is significant compared with the inductive reactance, the current lags the voltage by something less than 90 degrees (Fig 13-9) If R is small compared with XL, the current lag is almost 90 degrees; as R gets larger, the lag decreases A circuit with resistance and inductance is called an RL circuit The value of R in an RL circuit might increase relative to XL because resistance is deliberately placed in series with the inductance Or, it might happen because the ac frequency gets so low that XL decreases until it is in the same ball park with the loss resistance R in the coil winding In either case, the situation can be schematically represented by a coil in series with a resistor (Fig 13-10).

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The service provider issues a service order to create the circuit If, at some point in the future, the customer decides to change the circuit endpoints or upgrade the bandwidth, another service order must be issued, which would be PVC and is the most commonly deployed Frame Relay solution Frame Relay is also capable of supporting Switched Virtual Circuit (SVC) service, but SVCs are for the most part not available from service providers With SVC service, customers can make their own modifications to the circuit by accessing the Frame Relay switch in the central office (CO) and requesting changes However, service providers do not currently offer SVC service because of billing and tracking concerns (customer activities are difficult to monitor) Instead, they enable customers to create a fully meshed network between all locations for a very reasonable price.

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Problem 13-4 Suppose the inductive reactance in an RL circuit is 680 and the resistance is 840 . What is the phase angle The ratio XL/R is 680/840. A calculator will display this quotient as something like 0.8095 and some more digits. Find the arctangent of this number. You should get 38.99 and some more digits. This can be rounded off to 39.0 . Problem 13-5 Suppose an RL circuit operates at a frequency of 1.0 MHz with a resistance of 10 and an inductance of 90 H. What is the phase angle What does this tell us about the nature of this RL circuit at this frequency Find the inductive reactance using the formula XL = 6.28fL = 6.28 1.0 90 = 565 . Then find the ratio XL/R = 565/10 = 56.5. The phase angle is equal to arctan 56.5, which, rounded to two

If you know the values of XL and R, you can find the angle of lag, also called the RL phase angle, by plotting the point R jXL on the RL plane, drawing the vector from the origin 0 j0 out to that point, and then measuring the angle of the vector, counterclockwise from the resistance axis You can use a protractor to measure this angle, or you can compute its value using trigonometry In fact, you don t need to know the actual values of XL and R in order to find the angle of lag All you need to know is their ratio For example, if L 5 and R 3 , you will get the same angle as you would get if XL 50 and R 30 , or if XL 20 and R 12 .

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