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cin >> num; if(num==-2) { reset(); continue; } if(num != -1) cout << "Running average is: " << r_avg(num); cout << '\n'; } while(num != -1); return 0; } // ---------------------- Second File ---------------------static int sum=0, count=0; int r_avg(int i) { sum = sum + i; count++; return sum / count; } void reset() { sum = 0; count = 0; }

The network engineer typically is responsible for day-to-day operation of the network, including upgrading network devices and adding capacity to network devices and interconnects. A network engineer also acts as a second line of support for problems that the operations center engineer cannot resolve. The operations center engineer is the first line of support for network problems and is constantly in a reactive mode. Most large corporations have a centralized network monitoring center staffed with level-one engineers who attempt basic troubleshooting on network problems. These engineers monitor for events triggered by servers, workstations, or network devices with built-in ability to alert the operations center of potential problems. 29.3 Service Level Management in the Enterprise Environment Service level management (SLM) is the strategy of defining, controlling, and maintaining desired levels of IT service for the business end user. SLM encompasses a wide range of activities: acquiring information to determine appropriate service levels, monitoring for compliance, and providing continuous user feedback regarding IT performance. Business end users, together with the IT department, define the level of service needed to stay productive based on their level of network reliance. The level of service is turned into a set of objectives that IT can then monitor. Figure 29.4 shows the

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Figure 6-10

Similarly, DVD-R technology makes it possible for an independent lm company or video studio to create original masters and release them for replication in DVD-Video format. While the authoring tools and DVD recorders are still quite high in relation to CD-R levels, prices continue to drop as acceptance for this new medium grows. Software tools, such as Sonic Solutions DVDit!, bring impressive capabilities to the mainstream market, making it possible for anyone to turn digital video content into a published DVD work. Opportunities abound for independent developers to produce successful works and realize a pro t with unit sales in the hundreds, rather than the tens of thousands, as is the case with many commercial titles. The challenge, of course, is nding an audience in a market where many of the retail outlets are geared to large mainstream publishers of software, games, audio CDs, and educational titles. This chapter offers some suggestions for creatively marketing your original title that has been published to optical disc. It also discusses developing unique sales channels that you may not have even considered.

Three basic integral formulas can be obtained by taking the antiderivative of the differential formulas at the beginning of the previous section.

The way we distributed the energy in Sol. 5-3, by giving the minimum amount of energy to all but one molecule and then giving all of the remaining energy to the last molecule, is a good starting point for finding all possible distributions. It is the simplest distribution possible. It is the only distribution in which a single molecule has more than the minimum amount of energy. And that one molecule will always occupy the highest energy level available to any of the molecules. It is also the distribution with the smallest number of permutations (ways to arrange the molecules within the same distribution). The number of permutations for this distribution is simple to determine. Any one of the molecules could be the one molecule at this highest available energy level. (The remaining molecules are all on the lowest energy level.) Therefore the number of permutations for this simplest distribution is exactly equal to the number of molecules, as each molecule takes its turn being the one molecule at the highest energy level.

// Use foreach on a two-dimensional array. using System; class ForeachDemo2 { static void Main() { int sum = 0; int[,] nums = new int[3,5];

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