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cutting This information is also needed in planning the trajectory of the cutter of an NC machine tool 721 Tangent at a Point of a Cam Pro le To systematically obtain a relationship for determining the angle between the position vector of a point on the cam pro le and the tangent at that point, we refer to Fig 71 In that gure, l measures the arc length from a reference point Ol, and et is a unit vector parallel to line T, the tangent at point Q of the curve G Note that et points in the direction in which l grows It would be desirable to obtain an expression for vector et as a parametric representation of the position vector p of an arbitrary point of the contour, of components x and y, that is, p = [x, y]T However, x and y are usually available as functions of a parameter q different from l Hence, derivatives with respect to l will be obtained using the chain rule First, from elementary differential geometry, Marsden and Tromba (1988), we have et = where x( q ) x ( q ) and p ( q ) = p( q ) = y( q ) y ( q ) Next, since et is a unit vector, we have l ( q ) = p ( q ) = x 2 ( q ) + y 2 ( q ) where, obviously, the negative sign is used if l (q) < 0 Thus, if l ( q ) > 0 p ( q ) p ( q ) , et = - p ( q ) p ( q ) , if l ( q ) < 0

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As with the rst two trigonometric functions, we note that the tangent func tion takes each of the values 1, 1/ 3, 3 at many different points of its domain But Tan x takes each of these values at just one point of its domain The derivative of our new function may be calculated in the usual way The result is d 1 Tan 1 t = dt 1 + t2 Next we calculate some derivatives: EXAMPLE 639

Here, result is the name of the variable, which is of type double Because result has a floating-point type, it can hold values such as 12223, 0034, or 190 To better understand the difference between int and double, try the following program:

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/* This program illustrates the differences between int and double */ using System; class Example3 { static void Main() { int ivar; // this declares an int variable double dvar; // this declares a floating-point variable ivar = 100; // assign ivar the value 100

dp dp dq p ( q ) = = dl dq dl l ( q )

dvar = 1000; // assign dvar the value 1000 ConsoleWriteLine("Original value of ivar: " + ivar); ConsoleWriteLine("Original value of dvar: " + dvar); ConsoleWriteLine(); // print a blank line // Now, divide both by 3 ivar = ivar / 3; dvar = dvar / 30;

x =1

Part I:

(71)

ConsoleWriteLine("ivar after division: " + ivar); ConsoleWriteLine("dvar after division: " + dvar); } }

The output from this program is shown here:

(72)

Original value of ivar: 100 Original value of dvar: 100 ivar after division: 33 dvar after division: 333333333333333

Tan 1 (x 3 )

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As you can see, when ivar (an int variable) is divided by 3, a whole-number division is performed, and the outcome is 33 the fractional component is lost However, when dvar (a double variable) is divided by 3, the fractional component is preserved As the program shows, when you want to specify a floating-point value in a program, you must include a decimal point If you don t, it will be interpreted as an integer For example, in C#, the value 100 is an integer, but the value 1000 is a floating-point value There is one other new thing to notice in the program To print a blank line, simply call WriteLine( ) without any arguments The floating-point data types are often used when working with real-world quantities where fractional components are commonly needed For example, this program computes the area of a circle It uses the value 31416 for pi

(73)

// Compute the area of a circle using System; class Circle { static void Main() { double radius; double area; radius = 100; area = radius * radius * 31416; ConsoleWriteLine("Area is " + area); } }

The output from the program is shown here:

x= 2

(74)

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