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Table 13-1 summarizes the conversion between the Z-, Y-, h-, g-, and T-parameters. conversion to be possible, the determinant of the source parameters must be nonzero.

where, in the last two steps, we have respectively used the facts that the Xk are independent and are identically distributed. Now, by a Taylor series expansion, E[et(X1

Table 13-1 Z Z11 Z Z21 Z22 Dzz Y Z21 Dzz Dzz Z22 h Z21 Z22 1 Z11 g Z21 Z11 Z11 Z21 1 Z21 Z12 Z22 Z12 Dzz Z11 Dzz Z12 Z22 1 Z22 Z12 Z11 DZZ Z11 DZZ Z21 Z22 Z21 Y22 DYY Y21 DYY Y11 Y21 1 Y11 Y21 Y11 DYY Y22 Y21 Y22 Y22 Y21 DYY Y21 Y Y12 DYY Y11 DYY Y12 Y22 Y12 Y11 Dyy Y11 Y12 Y22 1 Y22 1 Y21 Y11 Y21 Dhh h22 h21 h22 1 h11 h21 h11 h11 h21 h22 Dhh h21 Dhh Dhh h21 h22 h21 h h12 h22 1 h22 h12 h11 Dnn h11 h12 h22 h12 Dhh h11 Dhh h11 h21 1 h21 1 g11 g21 g11 Dgg g22 g21 g22 g22 Dgg g21 Dgg g11 g21 1 g21 g11 g21 g g12 g11 Dgg g11 g12 g22 1 g22 g12 Dgg g11 Dgg g12 g22 g22 g21 Dgg g21 A C 1 C D B 1 B B D 1 D C A 1 A A C T DTT C D C DTT B A B DTT D C D DTT A B A B D

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m)>s1n]

cd s !n t2 t c E(X1 m) E[(X1 m)2] E(1) 2s2n s !n t t2 t2 c 1 c 1 (0) (s2) 2n 2s2n s !n t(X1 m) t2(X1 m)2 2s2n

13.1 Find the Z-parameters of the circuit in Fig. 13-16(a).

* E(etSn)

Z11 and Z21 are obtained by connecting a source to port #1 and leaving port #2 open [Fig. 13-16(b)]. The parallel and series combination of resistors produces Z11 V1 8 I1 I2 0 and Z21 V2 1 I1 I2 0 3

But the limit of this as n S ` is et 2>2, which is the moment generating function of the standardized normal distribution. Hence, by Theorem 3-10, page 80, the required result follows.

On 7/1/01, assume that task 3 has also been completed using 140 days of actual effort, so BCWP is 190 and EV is 190/330, or 57.5 percent. On 7/1/01, tasks 1, 2, 3, and 4 were actually completed. So BCWP is 190 days and BCWS is 250 days. Thus, SPI is 190/250 = 76 percent. The SV is 190 programmer-days 250 programmer-days = 60 programmer-days, or 60 programmer days behind. ACWP is the sum of actual effort for 1, 2, 3, and 4. So ACWP is 220 programmer-days. Tasks 1 through 5 were scheduled to have been completed, but only 1 through 4 were actually completed. CPI is 190/220 = 86.3 percent, and CV is 190 220, or 30 programmer-days behind.

Multinomial distribution 4.26. A box contains 5 red balls, 4 white balls, and 3 blue balls. A ball is selected at random from the box, its color is noted, and then the ball is replaced. Find the probability that out of 6 balls selected in this manner, 3 are red, 2 are white, and 1 is blue.

Similarly, Z22 and Z12 are obtained by connecting a source to port #2 and leaving port #1 open [Fig. 13-16(c)]. Z22 V2 8 I2 I1 0 9 Z12 V1 1 I2 I1 0 3

Method 1 (by formula) P(red at any drawing) 5 12 P(white at any drawing) 3 12 625 5184 4 12

Fig. 13-16

P(blue at any drawing) Then P(3 red, 2 white, 1 blue)

5 3 4 2 3 1 6! a b a b a b 3!2!1! 12 12 12

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