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Today this model is changing. Customer equipment has become remarkably intelligent, and many of the functions previously done within the network cloud are now performed at the edge. PBXs, computers, and other devices are now capable of making discriminatory decisions about required service levels, eliminating any need for the massive intelligence embedded in the core. At the same time, the bandwidth is migrating from the core of the network toward the customer as applications evolve to require it. Massive bandwidth still exists within the cloud, but the margins of the cloud are expanding toward the customer. The result of this evolution is a redefinition of the network s regions. Instead of a low-speed, low-intelligence access area and a high-speed, highly intelligent core, the intelligence has migrated outward to the margins of the network and the bandwidth, once exclusively a core resource, is now equally distributed at the edge. Thus, we see something of a core and edge distinction evolving as customer requirements change. One reason for this steady migration is the well-known fact within sales and marketing circles that products sell best when they are located close to the buying customer. They are also easier to customize for individual customers when they are physically closest to the situation for which the customer is buying them. In The Rise of the Stupid Network, David Isenberg makes the following observation:

Problem 14-3

Problem 14-6 What is the phase angle in the preceding circuit if the frequency is raised to 7.10 MHz You need to find the new value for XC, because it will change as a result of the frequency change. Calculating:

14-4 Capacitive reactance is negatively, and inversely, proportional to frequency (f) and also to capacitance (C).

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The Intelligent Network is a straight-line extension of four assumptions scarcity, voice, circuit switching, and control. Its primary design impetus was not customer service. Rather, the Intelligent Network was a telephone company attempt to engineer vendor independence, more automatic operation, and some intelligent new services into existing network architecture. However, even as it rolls out and matures, the Intelligent Network is being superseded by a Stupid Network, with nothing but dumb transport in the middle, and intelligent user-controlled endpoints, whose design is guided by plenty, not scarcity, where transport is guided by the needs of the data, not the design assumptions of the network.

X C = 1/(6.28 7.10 0.000150) = 1/0.006688 = 150 The ratio XC /R in this case is equal to 150/130, or 1.15. The phase angle is the arctangent of 1.15, which turns out to be 49.0 .

Points in the RC plane 251 In this problem, you need to put the numbers in the formula and solve for the unknown C. Begin with the equation 100 Dividing through by 100, you get: 1 1/(628 10.0 C) 1/(6.28 10.0 C)

Isenberg continues:

Multiply each side of this by C, and you obtain: C 1/(628 10.0)

Refer to the text in this chapter if necessary. A good score is at least 18 correct. Answers are in the back of the book. 1. As the size of the plates in a capacitor increases, all other things being equal, (a) the value of X C increases negatively. (b) the value of X C decreases negatively. (c) the value of X C does not change. (d) we cannot say what happens to X C without more data. 2. If the dielectric material between the plates of a capacitor is changed, all other things being equal, (a) the value of X C increases negatively. (b) the value of X C decreases negatively. (c) the value of X C does not change. (d) we cannot say what happens to X C without more data. 3. As the frequency of a wave gets lower, all other things being equal, the value of XC for a capacitor (a) increases negatively. (b) decreases negatively. (c) does not change. (d) depends on the current. 4. What is the reactance of a 330-pF capacitor at 800 kHz (a) 1.66 (b) 0.00166 (c) 603 (d) 603 k 5. Suppose a capacitor has a reactance of 4.50 at 377 Hz. What is its capacitance (a) 9.39 F (b) 93.9 F (c) 7.42 F (d) 74.2 F 6. Suppose a 47- F capacitor has a reactance of 47 . What is the frequency (a) 72 Hz (b) 7.2 MHz (c) 0.000072 Hz (d) 7.2 Hz

This can be solved easily enough. Divide out C 1/6280 on your calculator, and you ll get C 0.000159. Because the frequency is given in megahertz, this capacitance comes out in microfarads, so that C 0.000159 F. You might rather say that this is 159 pf (remember that 1 pF 0.000001 F). Admittedly, the arithmetic for dealing with capacitive reactance is a little messier than that for inductive reactance. This is the case for two reasons. First, you have to work with reciprocals, and therefore the numbers sometimes get awkward. Second, you have to watch those negative signs. It s easy to leave them out. But they re important when looking at reactances in the coordinate plane, because the minus sign tells you that the reactance is capacitive, rather than inductive.

A new network philosophy and architecture is replacing the vision of an Intelligent Network. The vision is one in which the public communications network would be engineered for always-on use, not intermittence and scarcity. It would be engineered for intelligence at the end-user s device, not in the network. And the network would be engineered simply to Deliver the Bits, Stupid, not for fancy network routing or smart number translation.

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