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In this chapter, we will take a look at two different projects The first project is a simple touch-tone generator that can be used to send DTMF signals through a radio transceiver, walkie-talkie, or wire line The second project uses the CM8880 to decode DTMF tones on a phone line or radio circuit and display the numbers on an LCD panel Both of our projects in this chapter will use the California Micro Devices model CM8880 touch-tone encoder/decoder chip; see App 1 on the CD-ROM for the data sheet Both projects use the BASIC STAMP 2 microprocessor and the new CM8880 DTMF encoder/decoder chip, a 20-pin in-line DIP package This encoder/decoder chip can be easily interfaced to the STAMP 2 controller and can be used to both generate and decode touch-tone tones; see App 1 for the data sheet The diagram in Fig.

3) d2 d1 d1 = (i 1) 2e 2e (142) n1 d2 = n2 d1 (141).

(38.10)

+ (void)initialize { AudioSessionInitialize(NULL, NULL, NULL, NULL); }

Pir(1 cos i)

where n = number of forces and reactions together. The proof uses Castigliano s theorem and may be found in Ref. [38.3].

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10-1 is a block diagram of the CM8880 touch-tone IC The chip requires only about six external components to form a complete encoder/decoder The CM8880 chip uses the ubiquitous 3579-MHz color burst crystal for its oscillator The touch-tone chip produces a binary output on pins D0 through D3, which directly connects to the STAMP 2 controller; see Table 10-2 Est on pin 18 is the early steering output signal, which indicates the detection of valid tone frequencies, and StGt on pin19 is the steering input and guard time output A time constant based on a capacitor and a resistor determines a valid signal duration time in which to accept a tone pair.

Downloaded from Digital Engineering Library @ McGraw-Hill (www.digitalengineeringlibrary.com) Copyright 2004 The McGraw-Hill Companies. All rights reserved. Any use is subject to the Terms of Use as given at the website.

Example 1. Find the shear force, bending moment, and torsional moment at the location of R3 for the ring shown in Fig. 38.4. Solution. Using the principles of statics, we first find the reactions to be R1 = R2 = R3 = Choosing point A at R3, the reduced loads are P0 = P2 = P3 = 0 R3 = 0 360 P1 = 30 F = 0.0833F 360 2 F 3

Passing NULL for all arguments gets access to the audio hardware without specifying any custom configuration.

P4 =

Three additional bits are used to select the modes of the CM8880: bits from the chip select (CS) pin, the read/write (RW) pin, and the resister select (RS0) pin; Table 10-3 depicts all the combinations of the three control pins The CM8880 is active only when CS equals 0 The RW bit determines the data direction (1 read and 0 write), and the RS bit determines whether the transaction involves data (DTMF tones) or internal functions (ie, 1 instructions/status and 0 data) Before you can use the CM8880, you have to set it up The device has two control registers, ie, A and B In the beginning of the program listing you will notice the setup of the registers; also refer to Tables 10-4 and 10-5..

= Fr (0 + 0.0833 sin 30 0.2222 sin 120 + 0.5833 sin 210 0.4444 sin 240 ) = 0.0576Fr In a similar manner, we find TA = 0.997Fr.

FIGURE 38.4 Ring loaded by the two forces F and supported by reactions R1, R2, and R3. The crosses indicate that the forces act downward; the heavy dots at the reactions R indicate an upward direction.

Downloaded from Digital Engineering Library @ McGraw-Hill (www.digitalengineeringlibrary.com) Copyright 2004 The McGraw-Hill Companies. All rights reserved. Any use is subject to the Terms of Use as given at the website.

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