.net pdf 417

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It isn t necessary to construct an entire RL plane to find phase angles. You can use a ruler that has centimeter (cm) and millimeter (mm) markings, and a protractor. First, draw a line a little more than 10 cm long, going from left to right on a sheet of paper. Use the ruler and a sharp pencil. Then, with the protractor, construct a line off the left end of this first line, going vertically upwards. Make this line at least 10 cm long. The horizontal line, or the one going to the right, is the R axis of a crude coordinate system. The vertical line, or the one going upwards, is the XL axis. If you know the values of XL and R, divide them down, or multiply them up (in your head) so that they re both between 0 and 100. For example, if XL 680 and R 840 , you can divide them both by 10 to get XL 68 and R 84. Plot these points lightly by making hash marks on the vertical and horizontal lines you ve drawn. The R mark will be 84 mm to the right of the origin, or intersection of the original two perpendicular lines. The XL mark will be 68 mm up from the origin. Draw a line connecting the two hash marks, as shown in Fig. 13-12. This line will run at a slant, and will form a triangle along with the two axes. Your hash marks, and the origin of the coordinate system, form vertices of a right triangle. The triangle is called right because one of its angles is a right angle (90 degrees.)

12. Each specific complex impedance value defined in the form R + jXL (a) corresponds to a specific point in the RL plane. (b) corresponds to a specific inductive reactance. (c) corresponds to a specific resistance. (d) All of the above are true. 13. A vector is defined as a mathematical quantity that has (a) magnitude and direction. (b) resistance and inductance. (c) resistance and reactance. (d) inductance and reactance. 14. In an RL circuit, as the ratio of inductive reactance to resistance (XL/R) decreases, the phase angle (a) increases. (b) decreases. (c) stays the same. (d) becomes alternately positive and negative. 15. In a circuit containing inductive reactance but no resistance, the phase angle is (a) constantly increasing. (b) constantly decreasing. (c) equal to 0 . (d) equal to 90 . 16. If the inductive reactance and the resistance in an RL circuit are equal (as expressed in ohms), then what is the phase angle (a) 0 (b) 45 (c) 90 (d) It depends on the actual values of the resistance and the inductive reactance. 17. In Fig. 13-14, the impedance shown is which of the following (a) 8.0 (b) 90 (c) 90 + j8.0 (d) 8.0 + j90 18. Note that in the diagram of Fig. 13-14, the R and XL scale divisions are of different sizes. The phase angle can nevertheless be determined. It is (a) about 50 , from the looks of it. (b) 48 , as measured with a protractor.

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Measure the angle between the slanted line and the horizontal, or R, axis. Extend one or both of the lines if necessary in order to get a good reading on the protractor. This angle will be between 0 and 90 degrees, and represents the phase angle in the RL circuit. The actual vector, R jXL , is found by constructing a rectangle using the origin and your two hash marks as three of the four vertices, and drawing new horizontal and vertical lines to complete the figure. The vector is the diagonal of this rectangle, as shown in Fig. 13-13. The phase angle is the angle between this vector and the R axis. It will be the same as the angle of the slanted line in Fig. 13-12.

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Have you heard that it is current, not voltage, that kills This is a literal truth, but it plays on semantics. It s like saying It s the heat, not the fire, that burns you. Naturally! But there can only be a deadly current if there is enough voltage to drive it through your body. You don t have to worry when handling flashlight cells, but you d better be extremely careful around household utility circuits. A voltage of 1.2 to 1.7 V can t normally pump a dangerous current through you, but a voltage of 117 V almost always can. In an electric circuit that always conducts equally well, the current is directly proportional to the applied voltage. If you double the voltage, you double the current. If the voltage is cut in half, the current is cut in half too. Figure 2-2 shows this relationship as a graph in general terms. It assumes that the power supply can provide the necessary number of charge carriers.

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