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I didn t finish the SeeqPod application immediately. Soon my membership in the iPhone developer program came through, and I got busier than I could remember being working on iPhone contracts. The SeeqPod idea got moved to the back burner. And then, when I needed the back burner, the idea got put in the fridge to finish later. Time passed, as it is wont to do. When I was able to return to the project, I made an awful discovery: SeeqPod had shut down its audio search system. Its web site was not clear about when or if it might return. I like learning new stuff and writing interesting new code that stretches my abilities. But I m also practical, and I hate doing all that and having no use for the result. Fortunately, audio streaming code is useful enough that it s not a solution that has to look hard for a problem to solve. While chatting in IRC one day, someone mentioned the idea of writing a custom iPhone app for a radio station. And the light bulb went on again. I ve been a member of KRCC, a local public radio station, for something like 17 years. Its broadcasts were available online. And I had met Delaney Utterback, the station manager, and was pretty sure he d like the idea. I contacted him, he was all for it, so I went to work applying my streaming code to their broadcasts.

The task of finding the deflection at any point on a ring with a loading like that of Fig. 38.3 is indeed difficult.The problem can be set up using Eq. (38.2), but the resulting integrals will be lengthy. The chances of making an error in signs or in terms during any of the simplification processes are very great. If a computer or even a programmable calculator is available, the integration can be performed using a numerical procedure such as Simpson s rule. Most of the user s manuals for programmable calculators contain such programs in the master library. When this approach is taken, the two terms behind each integral should not be multiplied out or simplified; reserve these tasks for the computer.

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Our first project, shown in Fig. 10-2, is a touch-tone generator that can be used to send touch-tone signals through a radio or wire circuit. This circuit can be interfaced to a micro-

38.4.1 A Ring with Symmetrical Loads A ring having three equally spaced loads, all equal in magnitude, with three equally spaced supports located midway between each pair of loads, has reactions at each support of R = F/2, M = 0.289Fr, and T = 0 by Biezeno s theorem.To find the moment and torque at any location from a reaction, we construct the diagram shown in Fig. 38.5. Then the moment and torque at A are M = M1 cos R1r sin = Fr (0.289 cos 0.5 sin ) T = M1 sin R1r (1 cos ) = Fr (0.289 sin 0.5 + 0.5 cos ) (38.11)

(38.12)

With the iPhone s NAND flash memory, writing is expensive both in terms of speed and in terms of hardware lifetime. It will eventually wear out with use. Apple recommends that you write to disk only when necessary. Since our application checks to see whether the data is stale, it is unlikely to download stock data more than once or twice per day, so you can reasonably store it to disk when it arrives. If your data were more often malleable, you might consider storing it only when the application closes or if you ran out of memory. In gogoDocs, we only download and write the updated feed if its last changed date is later than that of our cached information. This keeps the application from making unnecessary writes to the flash memory. Apple supplies a convenience method in your application s delegate where you can save data before the app closes:

FIGURE 38.5 The positive directions of the moment and torque axes are arbitrary. Note that R1 = F/2 and M1 = 0.289Fr.

Downloaded from Digital Engineering Library @ McGraw-Hill (www.digitalengineeringlibrary.com) Copyright 2004 The McGraw-Hill Companies. All rights reserved. Any use is subject to the Terms of Use as given at the website.

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Neglecting direct shear, the strain energy stored in the ring between any two supports is, from Table 38.2, U=2

/3 0

-applicationWillTerminate:

/3 0

0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15

(38.13)

(38.14)

From Eqs. (38.11) and (38.12), we find M = r(0.289 cos 0.5 sin ) F T = r(0.289 sin 0.5 + 0.5 cos ) F When these are substituted into Eq. (38.14), we get y= Fr3 A B + 2 EI GK (38.15)

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